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Papers 1 and 2 · Pure
8.5 Integration
Question 1 · 6 marks
Calculator allowed · Show full working
Spec and skills
Paper scope: Pure 1/2
Spec P8.5
Original practice question
I
=
∫
0
4
x
1
+
2
x
d
x
I = \displaystyle\int_0^4 \frac{x}{\sqrt{1 + 2x}}\,dx
I
=
∫
0
4
1
+
2
x
x
d
x
Use the substitution
u
=
1
+
2
x
u = 1 + 2x
u
=
1
+
2
x
to find the exact value of
I
I
I
.
Solutions relying entirely on calculator technology are not acceptable.
xⁿ
a/b
√
π
(
)