A-level Maths revision · Statistics

The binomial distribution

The idea

X∼B(n,p)X \sim B(n, p) counts successes in nn trials when the number of trials is fixed, trials are independent, there are two outcomes and pp stays the same. P(X=r)=(nr)pr(1−p)n−rP(X = r) = \binom{n}{r}p^r(1 - p)^{n - r}.

  1. Check the four conditions in context.
  2. Identify nn and pp.
  3. Use the formula, or your calculator's binomial PD function.

Watch out State the conditions in context, not just as a list.

See it worked

Worked example

X∼B(10,0.3)X \sim B(10, 0.3). Find P(X=2)P(X = 2).

  1. P(X=2)=(102)(0.3)2(0.7)8P(X = 2) = \binom{10}{2}(0.3)^2(0.7)^8.
  2. =45×0.09×0.057648= 45 \times 0.09 \times 0.057648.
  3. =0.2335= 0.2335 (4 d.p.).

Answer 0.23350.2335

Your turn

Question 1Calculator allowed3 marks

X∼B(8,0.25)X \sim B(8, 0.25). Find P(X=3)P(X = 3) to 4 decimal places.

Question 2Calculator allowed3 marks

X∼B(5,0.2)X \sim B(5, 0.2). Find P(X=0)P(X = 0).

Question 3Non-calculator3 marks

A student guesses all 2020 answers on a multiple-choice test with 44 options each. Explain why the number correct can be modelled by B(20,0.25)B(20, 0.25).

Write your answer, then show the working
  1. There is a fixed number of trials: 2020 questions.
  2. Each guess is right or wrong, with the same chance 14\frac{1}{4}.
  3. Guesses are independent of each other.

Answer Fixed number of questions, independent guesses, right or wrong, and p=0.25p = 0.25 each time

In past papers

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