A-level Maths revision · Pure, year 2

Sequences and sigma notation

The idea

A recurrence relation un+1=f(un)u_{n+1} = f(u_n) builds a sequence one term at a time from a first term. A sequence is increasing, decreasing or periodic (it repeats). ∑r=1n\sum_{r=1}^{n} means add the terms from r=1r = 1 to r=nr = n.

  1. Generate terms one at a time from u1u_1.
  2. Look for the pattern: steady growth, or a cycle that repeats.
  3. For a periodic sequence, use the remainder after dividing by the period.

Watch out Start from the right index: u1u_1 is the first term, so u2=f(u1)u_2 = f(u_1).

See it worked

Worked example

un+1=2un−1u_{n+1} = 2u_n - 1 with u1=3u_1 = 3. Find u2u_2, u3u_3 and u4u_4.

  1. u2=2(3)−1=5u_2 = 2(3) - 1 = 5.
  2. u3=2(5)−1=9u_3 = 2(5) - 1 = 9.
  3. u4=2(9)−1=17u_4 = 2(9) - 1 = 17.

Answer 5,9,175, 9, 17

Your turn

Question 1Non-calculator3 marks

un+1=3un+2u_{n+1} = 3u_n + 2 and u1=1u_1 = 1. Find u4u_4.

Question 2Non-calculator3 marks

Evaluate ∑r=110(2r+1)\sum_{r=1}^{10} (2r + 1).

Question 3Non-calculator3 marks

un+1=11−unu_{n+1} = \frac{1}{1 - u_n} and u1=2u_1 = 2. Find u100u_{100}.

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