A-level Maths revision · Statistics

Hypothesis test for a Normal mean

The idea

To test a mean, use the distribution of the sample mean: if X∼N(μ,σ2)X \sim N(\mu, \sigma^2), then Xˉ∼N(μ,σ2n)\bar{X} \sim N\left(\mu, \frac{\sigma^2}{n}\right). Assume H0H_0's mean, find the probability of a sample mean at least as extreme, and compare with the level.

  1. Write H0:μ=…H_0: \mu = \dots and H1H_1.
  2. Under H0H_0, Xˉ∼N(μ0,σ2n)\bar{X} \sim N\left(\mu_0, \frac{\sigma^2}{n}\right); standard error σn\frac{\sigma}{\sqrt{n}}.
  3. Find the pp-value or the critical value and conclude in context.

Watch out Use σn\frac{\sigma}{\sqrt{n}} for the sample mean, not σ\sigma.

See it worked

Worked example

A random sample of 3636 from N(μ,62)N(\mu, 6^2) has xˉ=52\bar{x} = 52. Test H0:μ=50H_0: \mu = 50 against H1:μ>50H_1: \mu > 50 at the 5%5\% level.

  1. Under H0H_0, Xˉ∼N(50,12)\bar{X} \sim N(50, 1^2), since 636=1\frac{6}{\sqrt{36}} = 1.
  2. P(Xˉ≥52)=P(Z≥2)=0.0228P(\bar{X} \ge 52) = P(Z \ge 2) = 0.0228.
  3. 0.0228<0.050.0228 < 0.05: reject H0H_0. There is evidence the mean is above 5050.

Answer Reject H0H_0

Your turn

Question 1Non-calculator3 marks

X∼N(μ,102)X \sim N(\mu, 10^2) and a sample of 2525 is taken. Find the standard deviation of Xˉ\bar{X}.

Question 2Calculator allowed3 marks

A random sample of 2525 from N(μ,152)N(\mu, 15^2) has xˉ=106\bar{x} = 106. For H0:μ=100H_0: \mu = 100, H1:μ>100H_1: \mu > 100, find the pp-value to 4 decimal places.

Question 3Calculator allowed3 marks

H0:μ=80H_0: \mu = 80, H1:μ>80H_1: \mu > 80, for a random sample of 1616 from N(μ,122)N(\mu, 12^2), at the 5%5\% level. Find the critical value of xˉ\bar{x} to 2 decimal places.

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