A-level Maths revision · Statistics

Histograms, box plots and outliers

The idea

In a histogram the area of each bar is proportional to its frequency, so the height is frequency density: frequencyclass width\frac{\text{frequency}}{\text{class width}}. A common outlier rule: a value is an outlier if it is more than 1.5×IQR1.5 \times \text{IQR} beyond the nearer quartile.

  1. Find each class width from the class boundaries.
  2. Frequency density == frequency ÷\div width; frequency == density ×\times width.
  3. Outlier fences: Q1−1.5×IQRQ_1 - 1.5 \times \text{IQR} and Q3+1.5×IQRQ_3 + 1.5 \times \text{IQR}.

Watch out A taller bar does not always hold more data: compare areas, not heights.

See it worked

Worked example

A class 10≤t<1510 \le t < 15 has frequency 3030. Find its frequency density.

  1. Class width: 15−10=515 - 10 = 5.
  2. Frequency density =305= \frac{30}{5}.
  3. =6= 6.

Answer 66

Your turn

Question 1Non-calculator3 marks

The class 20≤t<3020 \le t < 30 has frequency 4545. Find the height of its bar on a histogram drawn with frequency density.

Question 2Non-calculator3 marks

A histogram bar is 55 units wide with frequency density 3.23.2. How many observations does it represent?

Question 3Non-calculator3 marks

A data set has Q1=20Q_1 = 20 and Q3=32Q_3 = 32. Outliers are values more than 1.5×IQR1.5 \times \text{IQR} above Q3Q_3 or below Q1Q_1. Find the upper fence.

In past papers

25 official questions in 19 papers since 2018. The latest:

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